What is ((x+3)^2)/(49)-((y-1)^2)/(48)=1 ?

The solution to ((x+3)^2)/(49)-((y-1)^2)/(48)=1 is Hyperbola with (h,k)=(-3,1),a=7,b=4sqrt(3)

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((x+3)^2)/(49)-((y-1)^2)/(48)=1

\frac{( x + 3 ) ^{2}}{49} - \frac{( y - 1 ) ^{2}}{48} = 1

(h, k) = (- 3, 1), a = 7, b = 43

Solution steps

\frac{( x + 3 ) ^{2}}{49} - \frac{( y - 1 ) ^{2}}{48} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{49} - \frac{( y - 1 ) ^{2}}{48} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{7 ^{2}} - \frac{( y - 1 ) ^{2}}{( 4 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 1), a = 7, b = 43

5 x^{2} = 5 y^{2} + 45

- 3 y^{2} - 8 x + 4 x^{2} - 8 = 0

- \frac{y ^{2}}{49} + \frac{x ^{2}}{9} = 1

18 x^{2} = 28 + 8 y^{2}

4 x^{2} - 9 y^{2} - 48 x + 108 = 0

What is ((x+3)^2)/(49)-((y-1)^2)/(48)=1 ?
The solution to ((x+3)^2)/(49)-((y-1)^2)/(48)=1 is Hyperbola with (h,k)=(-3,1),a=7,b=4sqrt(3)