What is 18x^2=28+8y^2 ?

The solution to 18x^2=28+8y^2 is Hyperbola with (h,k)=(0,0),a=(sqrt(14))/3 ,b=sqrt(7/2)

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18x^2=28+8y^2

18 x^{2} = 28 + 8 y^{2}

(h, k) = (0, 0), a = \frac{14}{3}, b = \frac{7}{2}

Solution steps

18 x^{2} = 28 + 8 y^{2}

Rewrite

18 x^{2} = 28 + 8 y^{2}

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{14}{3} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{7}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{14}{3}, b = \frac{7}{2}

4 x^{2} - 9 y^{2} - 48 x + 108 = 0

\frac{( x - 9 ) ^{2}}{9} - \frac{( y + 4 ) ^{2}}{25} = 1

(a - b) (a + b) = 2 (3 a - 6)

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{20 0 ^{2}} = 1

9 x^{2} - 4 y^{2} + 18 x + 32 y = 119

What is 18x^2=28+8y^2 ?
The solution to 18x^2=28+8y^2 is Hyperbola with (h,k)=(0,0),a=(sqrt(14))/3 ,b=sqrt(7/2)