What is ((y+2)^2)/9-((x-1)^2)/4 =1 ?

The solution to ((y+2)^2)/9-((x-1)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=3,b=2

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((y+2)^2)/9-((x-1)^2)/4 =1

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{4} = 1

(h, k) = (1, - 2), a = 3, b = 2

Solution steps

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 3, b = 2

\frac{( y + 2 ) ^{2}}{36} - x^{2} = 1

\frac{( y - 2 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{9} = 1

16 x^{2} - 9 y^{2} = 576

x^{2} + 1 = 2 y^{2}

4 6^{2} x^{2} = 4 0^{2} y^{2} + 1600

What is ((y+2)^2)/9-((x-1)^2)/4 =1 ?
The solution to ((y+2)^2)/9-((x-1)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=3,b=2