What is ((3y+2x}{18})(\frac{3y-2x)/2)=1 ?

The solution to ((3y+2x}{18})(\frac{3y-2x)/2)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3

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((3y+2x}{18})(\frac{3y-2x)/2)=1

(\frac{3 y + 2 x}{18}) (\frac{3 y - 2 x}{2}) = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{3 y + 2 x}{18} \cdot \frac{3 y - 2 x}{2} = 1

Rewrite

\frac{3 y + 2 x}{18} \frac{3 y - 2 x}{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

\frac{1 x ^{2}}{4} - \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{20} - \frac{( y + 1 ) ^{2}}{10} = 1

4 x^{2} - 9 y^{2} = 1

\frac{( x - 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{36} = 1

x^{2} - y^{2} + 4 y = 0

What is ((3y+2x}{18})(\frac{3y-2x)/2)=1 ?
The solution to ((3y+2x}{18})(\frac{3y-2x)/2)=1 is Hyperbola with (h,k)=(0,0),a=2,b=3