What is ((((x-5)(x-5))/(y^2)))= 1/(y^2)+1 ?

The solution to ((((x-5)(x-5))/(y^2)))= 1/(y^2)+1 is Hyperbola with (h,k)=(5,0),a=1,b=1

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((((x-5)(x-5))/(y^2)))= 1/(y^2)+1

((\frac{( x - 5 ) ( x - 5 )}{y ^{2}})) = \frac{1}{y ^{2}} + 1

(h, k) = (5, 0), a = 1, b = 1

Solution steps

\frac{( x - 5 ) ( x - 5 )}{y ^{2}} = \frac{1}{y ^{2}} + 1

Rewrite

\frac{( x - 5 ) ( x - 5 )}{y ^{2}} - \frac{1}{y ^{2}} - 1 = 0

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 0), a = 1, b = 1

- 2 x^{2} + 4 y^{2} - 3 x - 43 y + 44 = 0

9 x^{2} - 36 x - 25 y^{2} = - 261

3 x^{2} - 6 x - y^{2} - 4 y - 4 = 0

4 y^{2} - 4 x^{2} + 1^{2} = 4

8 x + 2 y^{2} = 3 x^{2} + 3 y

What is ((((x-5)(x-5))/(y^2)))= 1/(y^2)+1 ?
The solution to ((((x-5)(x-5))/(y^2)))= 1/(y^2)+1 is Hyperbola with (h,k)=(5,0),a=1,b=1