What is yy=(x+7)^2+3 ?

The solution to yy=(x+7)^2+3 is Hyperbola with (h,k)=(-7,0),a=sqrt(3),b=sqrt(3)

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yy=(x+7)^2+3

yy = (x + 7)^{2} + 3

(h, k) = (- 7, 0), a = 3, b = 3

Solution steps

yy = (x + 7)^{2} + 3

Rewrite

yy - (x + 7)^{2} - 3 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( x - ( - 7 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 7, 0), a = 3, b = 3

y^{2} + \frac{4}{3} - x^{2} = 0

4 x^{2} - 16 y^{2} - 4 x + 32 y = 31

4 x^{2} - 16 y^{2} - 8 x - 96 y - 204 = 0

f (x) f (x) = 4 x^{2} - x + 2

\frac{( x - 2 ) ^{2}}{4} - (\frac{( y - 2 )}{5})^{2} = 1

What is yy=(x+7)^2+3 ?
The solution to yy=(x+7)^2+3 is Hyperbola with (h,k)=(-7,0),a=sqrt(3),b=sqrt(3)