What is ((y+3)^2)/9-((x-1)^2)/(25)=1 ?

The solution to ((y+3)^2)/9-((x-1)^2)/(25)=1 is Hyperbola with (h,k)=(1,-3),a=3,b=5

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((y+3)^2)/9-((x-1)^2)/(25)=1

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{25} = 1

(h, k) = (1, - 3), a = 3, b = 5

Solution steps

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 3), a = 3, b = 5

x^{2} = y^{2} + 13

y^{2} - x^{2} = \frac{9}{25}

x^{2} = y^{2} + 16

- x^{2} + 4 x + 3 y^{2} - 12 y - 4 = 0

16 \cdot (x^{2} - 2 x) - 25 (y^{2} - 4 y) = 484

What is ((y+3)^2)/9-((x-1)^2)/(25)=1 ?
The solution to ((y+3)^2)/9-((x-1)^2)/(25)=1 is Hyperbola with (h,k)=(1,-3),a=3,b=5