What is 16*(x^2-2x)-25(y^2-4y)=484 ?

The solution to 16*(x^2-2x)-25(y^2-4y)=484 is Hyperbola with (h,k)=(1,2),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16*(x^2-2x)-25(y^2-4y)=484

16 \cdot (x^{2} - 2 x) - 25 (y^{2} - 4 y) = 484

(h, k) = (1, 2), a = 5, b = 4

Solution steps

16 (x^{2} - 2 x) - 25 (y^{2} - 4 y) = 484

Rewrite

16 (x^{2} - 2 x) - 25 (y^{2} - 4 y) = 484

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{5 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 5, b = 4

\frac{( x - 2 ) ^{2}}{12} - \frac{( 3 y ^{2} + y )}{12} = 1

2 x - 4 x^{2} = - 9 y^{2} - 21 y - 50

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

(\frac{K ( x )}{2})^{2} = 4096 + 4096 - 128 x + x^{2}

1 \cdot 3 = (a + b) (a - b)

What is 16*(x^2-2x)-25(y^2-4y)=484 ?
The solution to 16*(x^2-2x)-25(y^2-4y)=484 is Hyperbola with (h,k)=(1,2),a=5,b=4