What is 4x^2-4y^2-32x+16y+39=0 ?

The solution to 4x^2-4y^2-32x+16y+39=0 is Hyperbola with (h,k)=(4,2),a= 3/2 ,b= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2-4y^2-32x+16y+39=0

4 x^{2} - 4 y^{2} - 32 x + 16 y + 39 = 0

(h, k) = (4, 2), a = \frac{3}{2}, b = \frac{3}{2}

Solution steps

4 x^{2} - 4 y^{2} - 32 x + 16 y + 39 = 0

Rewrite

4 x^{2} - 4 y^{2} - 32 x + 16 y + 39 = 0

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{( \frac{3}{2} ) ^{2}} - \frac{( y - 2 ) ^{2}}{( \frac{3}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 2), a = \frac{3}{2}, b = \frac{3}{2}

y^{2} - 2 y = x^{2} + 2 x + 1

p^{2} + 2021 = q^{2}

\frac{( y - 1 ) ^{2}}{4 ^{2}} - \frac{( x + 3 ) ^{2}}{5 ^{2}} = 1

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 3

3 x^{2} - 2 y^{2} - 12 x - 16 y + 4 = 0

What is 4x^2-4y^2-32x+16y+39=0 ?
The solution to 4x^2-4y^2-32x+16y+39=0 is Hyperbola with (h,k)=(4,2),a= 3/2 ,b= 3/2