What is ((y-1)^2)/(4^2)-((x+3)^2)/(5^2)=1 ?

The solution to ((y-1)^2)/(4^2)-((x+3)^2)/(5^2)=1 is Hyperbola with (h,k)=(-3,1),a=4,b=5

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((y-1)^2)/(4^2)-((x+3)^2)/(5^2)=1

\frac{( y - 1 ) ^{2}}{4 ^{2}} - \frac{( x + 3 ) ^{2}}{5 ^{2}} = 1

(h, k) = (- 3, 1), a = 4, b = 5

Solution steps

\frac{( y - 1 ) ^{2}}{4 ^{2}} - \frac{( x + 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 1), a = 4, b = 5

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 3

3 x^{2} - 2 y^{2} - 12 x - 16 y + 4 = 0

4 x^{2} - 5 y^{2} + 32 x + 30 y = 1

3 y^{2} - 5 x^{2} + 18 y - 40 x - 533 = 0

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

What is ((y-1)^2)/(4^2)-((x+3)^2)/(5^2)=1 ?
The solution to ((y-1)^2)/(4^2)-((x+3)^2)/(5^2)=1 is Hyperbola with (h,k)=(-3,1),a=4,b=5