What is ((x-7)^2}{16}-\frac{y^2)/9 =1 ?

The solution to ((x-7)^2}{16}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(7,0),a=4,b=3

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((x-7)^2}{16}-\frac{y^2)/9 =1

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

(h, k) = (7, 0), a = 4, b = 3

Solution steps

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 7 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (7, 0), a = 4, b = 3

16 x^{2} - 32 x = 9 y^{2} + 144 y - 16

y^{(2)} - x^{(2)} = (\frac{1}{49})

9 x^{2} - 4 y^{2} - 72 x + 8 y + 17 = 0

a^{2} - b^{2} = 300

a^{2} + 1 5^{2} = c^{2}

What is ((x-7)^2}{16}-\frac{y^2)/9 =1 ?
The solution to ((x-7)^2}{16}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(7,0),a=4,b=3