What is ((x+3)^2)/1-((y+3)^2)/3 =1 ?

The solution to ((x+3)^2)/1-((y+3)^2)/3 =1 is Hyperbola with (h,k)=(-3,-3),a=1,b=sqrt(3)

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((x+3)^2)/1-((y+3)^2)/3 =1

\frac{( x + 3 ) ^{2}}{1} - \frac{( y + 3 ) ^{2}}{3} = 1

(h, k) = (- 3, - 3), a = 1, b = 3

Solution steps

\frac{( x + 3 ) ^{2}}{1} - \frac{( y + 3 ) ^{2}}{3} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{1} - \frac{( y + 3 ) ^{2}}{3} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{1 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 3), a = 1, b = 3

(x - 9)^{2} - 9 (y + 7)^{2} = 1

4 x^{2} - 9 y^{2} + 24 x - 36 y - 36 = 0

\frac{x ^{2}}{4} - (\frac{( y + 1 )}{16})^{2} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

\frac{( x + 4 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{4} = 1

What is ((x+3)^2)/1-((y+3)^2)/3 =1 ?
The solution to ((x+3)^2)/1-((y+3)^2)/3 =1 is Hyperbola with (h,k)=(-3,-3),a=1,b=sqrt(3)