What is the vertices (y^2)/4-(x^2)/1 =1 ?

The vertices (y^2)/4-(x^2)/1 =1 is (0,2),(0,-2)

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vertices (y^2)/4-(x^2)/1 =1

vertices

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

\frac{( y + 3 ) ^{2}}{25} - \frac{( x - 2 ) ^{2}}{49} = 1

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

9 y^{2} - 4 x^{2} + 32 x - 36 y - 64 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

What is the vertices (y^2)/4-(x^2)/1 =1 ?
The vertices (y^2)/4-(x^2)/1 =1 is (0,2),(0,-2)