What is the vertices (y^2)/(36)-(x^2)/(81)=1 ?

The vertices (y^2)/(36)-(x^2)/(81)=1 is (0,6),(0,-6)

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vertices (y^2)/(36)-(x^2)/(81)=1

vertices

\frac{y ^{2}}{36} - \frac{x ^{2}}{81} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 9

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

\frac{x ^{2}}{4} - \frac{y ^{2}}{1} = 1

y^{2} - x^{2} = 25

\frac{( y - 8 ) ^{2}}{4} - \frac{( x - 5 ) ^{2}}{9} = 1

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

- 4 x^{2} + y^{2} = 16

What is the vertices (y^2)/(36)-(x^2)/(81)=1 ?
The vertices (y^2)/(36)-(x^2)/(81)=1 is (0,6),(0,-6)