What is the vertices-25x^2+9y^2=225 ?

The vertices-25x^2+9y^2=225 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices-25x^2+9y^2=225

vertices

- 25 x^{2} + 9 y^{2} = 225

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 25 x^{2} + 9 y^{2} = 225 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 3

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

9 y^{2} - x^{2} + 54 y + 2 x + 62 = 0

x^{2} - y^{2} = 6

4 x^{2} - y^{2} + 24 x - 4 y = 4

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{22} = 1

What is the vertices-25x^2+9y^2=225 ?
The vertices-25x^2+9y^2=225 is (0,5),(0,-5)