What is the vertices (x^2)/(29)-(y^2)/(20)=1 ?

The vertices (x^2)/(29)-(y^2)/(20)=1 is (sqrt(29),0),(-sqrt(29),0)

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vertices (x^2)/(29)-(y^2)/(20)=1

vertices

\frac{x ^{2}}{29} - \frac{y ^{2}}{20} = 1

(29, 0), (- 29, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{29} - \frac{y ^{2}}{20} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 29, b = 25

(0 + 29, 0), (0 - 29, 0)

Refine

(29, 0), (- 29, 0)

y^{2} - x^{2} = \frac{9}{25}

16 y^{2} - 9 x^{2} + 36 x + 96 y - 36 = 0

- 25 x^{2} + 4 y^{2} = 100

\frac{y ^{2}}{144} - \frac{x ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

What is the vertices (x^2)/(29)-(y^2)/(20)=1 ?
The vertices (x^2)/(29)-(y^2)/(20)=1 is (sqrt(29),0),(-sqrt(29),0)