What is the vertices ((y+4)^2)/4-((x+4)^2)/(25)=1 ?

The vertices ((y+4)^2)/4-((x+4)^2)/(25)=1 is (-4,-2),(-4,-6)

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vertices ((y+4)^2)/4-((x+4)^2)/(25)=1

vertices

\frac{( y + 4 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{25} = 1

(- 4, - 2), (- 4, - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{( y + 4 ) ^{2}}{4} - \frac{( x + 4 ) ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (- 4, - 4), a = 2, b = 5

(- 4, - 4 + 2), (- 4, - 4 - 2)

Refine

(- 4, - 2), (- 4, - 6)

4 x^{2} - 5 y^{2} + 20 = 0

9 (x - 3)^{2} - 4 (y - 1)^{2} = - 36

\frac{y ^{2}}{144} - \frac{x ^{2}}{81} = 1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

What is the vertices ((y+4)^2)/4-((x+4)^2)/(25)=1 ?
The vertices ((y+4)^2)/4-((x+4)^2)/(25)=1 is (-4,-2),(-4,-6)