What is the vertices (y^2)/(144)-(x^2)/(81)=1 ?

The vertices (y^2)/(144)-(x^2)/(81)=1 is (0,12),(0,-12)

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vertices (y^2)/(144)-(x^2)/(81)=1

vertices

\frac{y ^{2}}{144} - \frac{x ^{2}}{81} = 1

(0, 12), (0, - 12)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{144} - \frac{x ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 12, b = 9

(0, 0 + 12), (0, 0 - 12)

Refine

(0, 12), (0, - 12)

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

\frac{y ^{2}}{25} - x^{2} = 1

- 9 x^{2} + 16 y^{2} - 36 x - 160 y + 220 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

What is the vertices (y^2)/(144)-(x^2)/(81)=1 ?
The vertices (y^2)/(144)-(x^2)/(81)=1 is (0,12),(0,-12)