What is the vertices (y^2)/(25)-x^2=1 ?

The vertices (y^2)/(25)-x^2=1 is (0,5),(0,-5)

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vertices (y^2)/(25)-x^2=1

vertices

\frac{y ^{2}}{25} - x^{2} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - x^{2} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 1

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

- 9 x^{2} + 16 y^{2} - 36 x - 160 y + 220 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{64} = 1

What is the vertices (y^2)/(25)-x^2=1 ?
The vertices (y^2)/(25)-x^2=1 is (0,5),(0,-5)