What is the vertices (x^2)/(49)-(y^2)/(81)=1 ?

The vertices (x^2)/(49)-(y^2)/(81)=1 is (7,0),(-7,0)

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vertices (x^2)/(49)-(y^2)/(81)=1

vertices

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

(7, 0), (- 7, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 9

(0 + 7, 0), (0 - 7, 0)

Refine

(7, 0), (- 7, 0)

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{64} = 1

9 y^{2} - 25 x^{2} = 225

2 x^{2} - y^{2} - 2 y = - 5

9 y^{2} + 36 y - 4 x^{2} - 24 x - 36 = 0

What is the vertices (x^2)/(49)-(y^2)/(81)=1 ?
The vertices (x^2)/(49)-(y^2)/(81)=1 is (7,0),(-7,0)