What is the foci x^2-y^2=9 ?

The foci x^2-y^2=9 is (3sqrt(2),0),(-3sqrt(2),0)

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foci x^2-y^2=9

foci

x^{2} - y^{2} = 9

(32, 0), (- 32, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 9 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 3^{2} : 32

(0 + 32, 0), (0 - 32, 0)

Refine

(32, 0), (- 32, 0)

x^{2} - y^{2} = 2

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{5} = 1

x^{2} - y^{2} \geq 1

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1