Solution
foci
Solution
Solution steps
Rewrite as
Calculate Hyperbola properties
Right-left Hyperbola with
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Popular Examples
foci ((x-6)^2}{16}-\frac{(y-2)^2)/9 =1foci foci (y^2)/(16)-(x^2)/(25)=1foci foci-x^2+4y^2-2x-16y+11=0foci foci 9x^2-16y^2-18x-64y-199=0foci foci (x^2}{1^2}-\frac{y^2)/8 =1foci
Frequently Asked Questions (FAQ)
What is the foci x^2-y^2>= 1 ?
The foci x^2-y^2>= 1 is (sqrt(2),0),(-sqrt(2),0)