What is the foci 9x^2-16y^2-18x-64y-199=0 ?

The foci 9x^2-16y^2-18x-64y-199=0 is (6,-2),(-4,-2)

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foci 9x^2-16y^2-18x-64y-199=0

foci

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

(6, - 2), (- 4, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0 :

Right-left Hyperbola with

(h, k) = (1, - 2), a = 4, b = 3

(1 + c, - 2), (1 - c, - 2)

Compute

c :

c = 4^{2} + 3^{2} : 5

(1 + 5, - 2), (1 - 5, - 2)

Refine

(6, - 2), (- 4, - 2)

\frac{x ^{2}}{1 ^{2}} - \frac{y ^{2}}{8} = 1

3 x^{2} - 15 y^{2} + 2 x - 3 y = 4

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

9 x^{2} - 4 y^{2} - 54 x - 8 y + 113 = 0

What is the foci 9x^2-16y^2-18x-64y-199=0 ?
The foci 9x^2-16y^2-18x-64y-199=0 is (6,-2),(-4,-2)