What is the foci (x^2)/4-(3y^2)/4 =1 ?

The foci (x^2)/4-(3y^2)/4 =1 is (4/(sqrt(3)),0),(-4/(sqrt(3)),0)

Popular >

foci (x^2)/4-(3y^2)/4 =1

foci

\frac{x ^{2}}{4} - \frac{3 y ^{2}}{4} = 1

(\frac{4}{3}, 0), (- \frac{4}{3}, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{3 y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = \frac{2}{3}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + (\frac{2}{3})^{2} : \frac{4}{3}

(0 + \frac{4}{3}, 0), (0 - \frac{4}{3}, 0)

Refine

(\frac{4}{3}, 0), (- \frac{4}{3}, 0)

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

\frac{( x + 1.6 ) ^{2}}{1} - \frac{( y + 1 ) ^{2}}{0.07} = 1

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

What is the foci (x^2)/4-(3y^2)/4 =1 ?
The foci (x^2)/4-(3y^2)/4 =1 is (4/(sqrt(3)),0),(-4/(sqrt(3)),0)