What is the foci (y^2)/4-(x^2)/(25)=1 ?

The foci (y^2)/4-(x^2)/(25)=1 is (0,sqrt(29)),(0,-sqrt(29))

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foci (y^2)/4-(x^2)/(25)=1

foci

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

(0, 29), (0, - 29)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 5^{2} : 29

(0, 0 + 29), (0, 0 - 29)

Refine

(0, 29), (0, - 29)

25 y^{2} - 36 (x - 8)^{2} = 900

\frac{y ^{2}}{16} - \frac{x ^{2}}{36} = 1

4 y^{2} - 9 x^{2} = 36

9 x^{2} - y^{2} = 36

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

What is the foci (y^2)/4-(x^2)/(25)=1 ?
The foci (y^2)/4-(x^2)/(25)=1 is (0,sqrt(29)),(0,-sqrt(29))