What is the foci 9x^2-4y^2-18x+16y-43=0 ?

The foci 9x^2-4y^2-18x+16y-43=0 is (1+sqrt(13),2),(1-sqrt(13),2)

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foci 9x^2-4y^2-18x+16y-43=0

foci

9 x^{2} - 4 y^{2} - 18 x + 16 y - 43 = 0

(1 + 13, 2), (1 - 13, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} - 18 x + 16 y - 43 = 0 :

Right-left Hyperbola with

(h, k) = (1, 2), a = 2, b = 3

(1 + c, 2), (1 - c, 2)

Compute

c :

c = 2^{2} + 3^{2} : 13

(1 + 13, 2), (1 - 13, 2)

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1

\frac{x ^{2}}{100} - \frac{y ^{2}}{36} = 1

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{49} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{25} = 1

What is the foci 9x^2-4y^2-18x+16y-43=0 ?
The foci 9x^2-4y^2-18x+16y-43=0 is (1+sqrt(13),2),(1-sqrt(13),2)