What is the foci-(x^2)/(16)+(y^2)/(36)=1 ?

The foci-(x^2)/(16)+(y^2)/(36)=1 is (0,2sqrt(13)),(0,-2sqrt(13))

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foci-(x^2)/(16)+(y^2)/(36)=1

foci

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

(0, 213), (0, - 213)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 4^{2} : 213

(0, 0 + 213), (0, 0 - 213)

Refine

(0, 213), (0, - 213)

\frac{y ^{2}}{25} - \frac{( x - 2 ) ^{2}}{0} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{144} = 1

\frac{( y - 3 ) ^{2}}{36} - \frac{( x + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{55} = 1

What is the foci-(x^2)/(16)+(y^2)/(36)=1 ?
The foci-(x^2)/(16)+(y^2)/(36)=1 is (0,2sqrt(13)),(0,-2sqrt(13))