What is the foci (x^2)/9-(y^2)/(55)=1 ?

The foci (x^2)/9-(y^2)/(55)=1 is (8,0),(-8,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/9-(y^2)/(55)=1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{55} = 1

(8, 0), (- 8, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{55} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 55

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 55^{2} : 8

(0 + 8, 0), (0 - 8, 0)

Refine

(8, 0), (- 8, 0)

\frac{( y + 3 ) ^{2}}{4} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{( y + 1 ) ^{2}}{16} - \frac{( x + 1 ) ^{2}}{16} = 1

4 x^{2} - y^{2} = 16

- 9 x^{2} + y^{2} + 18 x - 45 = 0

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

What is the foci (x^2)/9-(y^2)/(55)=1 ?
The foci (x^2)/9-(y^2)/(55)=1 is (8,0),(-8,0)