What is the foci 4x^2-y^2=16 ?

The foci 4x^2-y^2=16 is (2sqrt(5),0),(-2sqrt(5),0)

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foci 4x^2-y^2=16

foci

4 x^{2} - y^{2} = 16

(25, 0), (- 25, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

4 x^{2} - y^{2} = 16 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 4^{2} : 25

(0 + 25, 0), (0 - 25, 0)

Refine

(25, 0), (- 25, 0)

- 9 x^{2} + y^{2} + 18 x - 45 = 0

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

9 x^{2} - 4 y^{2} + 54 x - 8 y + 78 = 0

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

What is the foci 4x^2-y^2=16 ?
The foci 4x^2-y^2=16 is (2sqrt(5),0),(-2sqrt(5),0)