What is the foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?

The foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is (-1,4+sqrt(29)),(-1,4-sqrt(29))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1

foci

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

(- 1, 4 + 29), (- 1, 4 - 29)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (- 1, 4), a = 5, b = 2

(- 1, 4 + c), (- 1, 4 - c)

Compute

c :

c = 5^{2} + 2^{2} : 29

(- 1, 4 + 29), (- 1, 4 - 29)

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

9 x^{2} - 4 y^{2} + 54 x - 8 y + 78 = 0

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

What is the foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?
The foci ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is (-1,4+sqrt(29)),(-1,4-sqrt(29))