What is the foci (x^2)/1-(y^2)/9 =1 ?

The foci (x^2)/1-(y^2)/9 =1 is (sqrt(10),0),(-sqrt(10),0)

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foci (x^2)/1-(y^2)/9 =1

foci

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1^{2} + 3^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

y^{2} - x^{2} = 25

\frac{x ^{2}}{140} - \frac{( y - 6 ) ^{2}}{4} = - 1

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{4} - y^{2} = 1

\frac{y ^{2}}{25} - x^{2} = 1

What is the foci (x^2)/1-(y^2)/9 =1 ?
The foci (x^2)/1-(y^2)/9 =1 is (sqrt(10),0),(-sqrt(10),0)