What is the foci (x^2}{140}-\frac{(y-6)^2)/4 =-1 ?

The foci (x^2}{140}-\frac{(y-6)^2)/4 =-1 is (0,18),(0,-6)

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foci (x^2}{140}-\frac{(y-6)^2)/4 =-1

foci

\frac{x ^{2}}{140} - \frac{( y - 6 ) ^{2}}{4} = - 1

(0, 18), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{x ^{2}}{140} - \frac{( y - 6 ) ^{2}}{4} = - 1 :

Up-down Hyperbola with

(h, k) = (0, 6), a = 2, b = 235

(0, 6 + c), (0, 6 - c)

Compute

c :

c = 2^{2} + (235)^{2} : 12

(0, 6 + 12), (0, 6 - 12)

Refine

(0, 18), (0, - 6)

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{4} - y^{2} = 1

\frac{y ^{2}}{25} - x^{2} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{48} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{16} = 1

What is the foci (x^2}{140}-\frac{(y-6)^2)/4 =-1 ?
The foci (x^2}{140}-\frac{(y-6)^2)/4 =-1 is (0,18),(0,-6)