What is the foci (x^2)/(49)-y^2=1 ?

The foci (x^2)/(49)-y^2=1 is (5sqrt(2),0),(-5sqrt(2),0)

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foci (x^2)/(49)-y^2=1

foci

\frac{x ^{2}}{49} - y^{2} = 1

(52, 0), (- 52, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 1^{2} : 52

(0 + 52, 0), (0 - 52, 0)

Refine

(52, 0), (- 52, 0)

4 x^{2} - 4 y^{2} + 20 x - 16 y + 25 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{81} = 1

3 x^{2} - 4 y^{2} = 12

5 x^{2} - 5 y^{2} + 20 x - 60 y = 185

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

What is the foci (x^2)/(49)-y^2=1 ?
The foci (x^2)/(49)-y^2=1 is (5sqrt(2),0),(-5sqrt(2),0)