What is the foci 3x^2-4y^2=12 ?

The foci 3x^2-4y^2=12 is (sqrt(7),0),(-sqrt(7),0)

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foci 3x^2-4y^2=12

foci

3 x^{2} - 4 y^{2} = 12

(7, 0), (- 7, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

3 x^{2} - 4 y^{2} = 12 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 7

(0 + 7, 0), (0 - 7, 0)

Refine

(7, 0), (- 7, 0)

5 x^{2} - 5 y^{2} + 20 x - 60 y = 185

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

25 y^{2} - 16 x^{2} = 400

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1

4 x^{2} - 3 y^{2} - 8 x - 8 = 0

What is the foci 3x^2-4y^2=12 ?
The foci 3x^2-4y^2=12 is (sqrt(7),0),(-sqrt(7),0)