What is the foci (x^2)/9-(y^2)/(49)=1 ?

The foci (x^2)/9-(y^2)/(49)=1 is (sqrt(58),0),(-sqrt(58),0)

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foci (x^2)/9-(y^2)/(49)=1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1

(58, 0), (- 58, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 7^{2} : 58

(0 + 58, 0), (0 - 58, 0)

Refine

(58, 0), (- 58, 0)

4 x^{2} - 3 y^{2} - 8 x - 8 = 0

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{5625} - \frac{y ^{2}}{1600} = 1

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

9 x^{2} - 4 y^{2} + 54 x + 16 y + 29 = 0

What is the foci (x^2)/9-(y^2)/(49)=1 ?
The foci (x^2)/9-(y^2)/(49)=1 is (sqrt(58),0),(-sqrt(58),0)