What is the foci (x^2)/(5625)-(y^2)/(1600)=1 ?

The foci (x^2)/(5625)-(y^2)/(1600)=1 is (85,0),(-85,0)

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foci (x^2)/(5625)-(y^2)/(1600)=1

foci

\frac{x ^{2}}{5625} - \frac{y ^{2}}{1600} = 1

(85, 0), (- 85, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{5625} - \frac{y ^{2}}{1600} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 75, b = 40

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7 5^{2} + 4 0^{2} : 85

(0 + 85, 0), (0 - 85, 0)

Refine

(85, 0), (- 85, 0)

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

9 x^{2} - 4 y^{2} + 54 x + 16 y + 29 = 0

8 y^{2} - 4 x^{2} = 4

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

\frac{( y + \frac{7}{2} ) ^{2}}{25} - \frac{( x - \frac{9}{2} ) ^{2}}{25} = 1

What is the foci (x^2)/(5625)-(y^2)/(1600)=1 ?
The foci (x^2)/(5625)-(y^2)/(1600)=1 is (85,0),(-85,0)