What is the foci 8y^2-4x^2=4 ?

The foci 8y^2-4x^2=4 is (0,sqrt(3/2)),(0,-sqrt(3/2))

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foci 8y^2-4x^2=4

foci

8 y^{2} - 4 x^{2} = 4

(0, \frac{3}{2}), (0, - \frac{3}{2})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

8 y^{2} - 4 x^{2} = 4 :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{1}{2}, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = \frac{1}{2}^{2} + 1^{2} : \frac{3}{2}

(0, 0 + \frac{3}{2}), (0, 0 - \frac{3}{2})

Refine

(0, \frac{3}{2}), (0, - \frac{3}{2})

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

\frac{( y + \frac{7}{2} ) ^{2}}{25} - \frac{( x - \frac{9}{2} ) ^{2}}{25} = 1

y^{2} - 4 x^{2} = 16

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1

x^{2} - \frac{y ^{2}}{25} = 1

What is the foci 8y^2-4x^2=4 ?
The foci 8y^2-4x^2=4 is (0,sqrt(3/2)),(0,-sqrt(3/2))