What is the foci (y^2)/5-(x^2)/5 =1 ?

The foci (y^2)/5-(x^2)/5 =1 is (0,sqrt(10)),(0,-sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2)/5-(x^2)/5 =1

foci

\frac{y ^{2}}{5} - \frac{x ^{2}}{5} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{5} - \frac{x ^{2}}{5} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 5^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

(x - 3)^{2} - \frac{y ^{2}}{9} = 1

\frac{1}{144} x^{2} - \frac{1}{196} y^{2} = 1

- 9 x^{2} + y^{2} = 36

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1

(\frac{x - 3}{16})^{2} - \frac{( y - 1 ) ^{2}}{9} = 1

What is the foci (y^2)/5-(x^2)/5 =1 ?
The foci (y^2)/5-(x^2)/5 =1 is (0,sqrt(10)),(0,-sqrt(10))