What is the foci (y^2)/(64)-(x^2)/(49)=1 ?

The foci (y^2)/(64)-(x^2)/(49)=1 is (0,sqrt(113)),(0,-sqrt(113))

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foci (y^2)/(64)-(x^2)/(49)=1

foci

\frac{y ^{2}}{64} - \frac{x ^{2}}{49} = 1

(0, 113), (0, - 113)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{49} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 7

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} + 7^{2} : 113

(0, 0 + 113), (0, 0 - 113)

Refine

(0, 113), (0, - 113)

+ \frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

- 4 x^{2} + y^{2} = 36

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

x^{2} - y^{2} = 100

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

What is the foci (y^2)/(64)-(x^2)/(49)=1 ?
The foci (y^2)/(64)-(x^2)/(49)=1 is (0,sqrt(113)),(0,-sqrt(113))