What is the foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 ?

The foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 is (2,3+8sqrt(2)),(2,3-8sqrt(2))

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foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1

foci

\frac{( y - 3 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1

(2, 3 + 82), (2, 3 - 82)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 3 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1 :

Up-down Hyperbola with

(h, k) = (2, 3), a = 8, b = 8

(2, 3 + c), (2, 3 - c)

Compute

c :

c = 8^{2} + 8^{2} : 82

(2, 3 + 82), (2, 3 - 82)

\frac{x ^{2}}{18} - \frac{y ^{2}}{7} = 1

\frac{( x ^{2} )}{4} - 0.14 y^{2} = 1

\frac{x ^{2}}{( \frac{64}{7} )} - \frac{y ^{2}}{( \frac{48}{7} )} = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

What is the foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 ?
The foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 is (2,3+8sqrt(2)),(2,3-8sqrt(2))