What is the foci (x^2)/(81)-(y^2)/(49)=1 ?

The foci (x^2)/(81)-(y^2)/(49)=1 is (sqrt(130),0),(-sqrt(130),0)

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foci (x^2)/(81)-(y^2)/(49)=1

foci

\frac{x ^{2}}{81} - \frac{y ^{2}}{49} = 1

(130, 0), (- 130, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{81} - \frac{y ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 9, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} + 7^{2} : 130

(0 + 130, 0), (0 - 130, 0)

Refine

(130, 0), (- 130, 0)

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

x^{2} - y^{2} = - 4

- 4 x^{2} + y^{2} - 16 x - 52 = 0

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{25} = 1

What is the foci (x^2)/(81)-(y^2)/(49)=1 ?
The foci (x^2)/(81)-(y^2)/(49)=1 is (sqrt(130),0),(-sqrt(130),0)