What is the foci 1-(x^2)/4+(y-1)^2=0 ?

The foci 1-(x^2)/4+(y-1)^2=0 is (sqrt(5),1),(-sqrt(5),1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 1-(x^2)/4+(y-1)^2=0

foci

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0

(5, 1), (- 5, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0 :

Right-left Hyperbola with

(h, k) = (0, 1), a = 2, b = 1

(0 + c, 1), (0 - c, 1)

Compute

c :

c = 2^{2} + 1^{2} : 5

(0 + 5, 1), (0 - 5, 1)

Refine

(5, 1), (- 5, 1)

x^{2} - y^{2} = 4 x

y^{2} - x^{2} = 1

(y + 4)^{2} - \frac{( x - 2 ) ^{2}}{4} = 1

\frac{( x - 6 ) ^{2}}{8} - \frac{( y - 5 ) ^{2}}{1} = 1

\frac{x ^{2}}{16} - \frac{( y + 5 ) ^{2}}{9} = 1

What is the foci 1-(x^2)/4+(y-1)^2=0 ?
The foci 1-(x^2)/4+(y-1)^2=0 is (sqrt(5),1),(-sqrt(5),1)