What is the foci ((x-1)^2)/(16)-((y-7)^2)/(20)=1 ?

The foci ((x-1)^2)/(16)-((y-7)^2)/(20)=1 is (7,7),(-5,7)

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foci ((x-1)^2)/(16)-((y-7)^2)/(20)=1

foci

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 7 ) ^{2}}{20} = 1

(7, 7), (- 5, 7)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 7 ) ^{2}}{20} = 1 :

Right-left Hyperbola with

(h, k) = (1, 7), a = 4, b = 25

(1 + c, 7), (1 - c, 7)

Compute

c :

c = 4^{2} + (25)^{2} : 6

(1 + 6, 7), (1 - 6, 7)

Refine

(7, 7), (- 5, 7)

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

\frac{y ^{2}}{6} - \frac{x ^{2}}{11} = 1

4 x^{2} - y^{2} - 32 x + 60 = 0

What is the foci ((x-1)^2)/(16)-((y-7)^2)/(20)=1 ?
The foci ((x-1)^2)/(16)-((y-7)^2)/(20)=1 is (7,7),(-5,7)