What is the foci x^2-16y^2=64 ?

The foci x^2-16y^2=64 is (2sqrt(17),0),(-2sqrt(17),0)

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foci x^2-16y^2=64

foci

x^{2} - 16 y^{2} = 64

(217, 0), (- 217, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 16 y^{2} = 64 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 8, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} + 2^{2} : 217

(0 + 217, 0), (0 - 217, 0)

Refine

(217, 0), (- 217, 0)

(\frac{( x ^{2} )}{27}) - \frac{( ( y ) ^{2} )}{36} = 1

x^{2} - y^{2} - 6 x + 16 y - 119 = 0

9 x^{2} - 25 y^{2} = 900

(\frac{x - 5}{8})^{2} - (\frac{y + 2}{7})^{2} = 1

3 x^{2} - y^{2} = 3

What is the foci x^2-16y^2=64 ?
The foci x^2-16y^2=64 is (2sqrt(17),0),(-2sqrt(17),0)