What is the center ((x+1)^2)/(25)-((y-4)^2)/(144)=1 ?

The center ((x+1)^2)/(25)-((y-4)^2)/(144)=1 is (-1,4)

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center ((x+1)^2)/(25)-((y-4)^2)/(144)=1

center

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

(- 1, 4)

Solution steps

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} - \frac{( y - 4 ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 5, b = 12

And the center is:

(- 1, 4)

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{5} = 1

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

What is the center ((x+1)^2)/(25)-((y-4)^2)/(144)=1 ?
The center ((x+1)^2)/(25)-((y-4)^2)/(144)=1 is (-1,4)