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Popular >

foci 9x^2+25y^2=225

Solution

foci

9 x^{2} + 25 y^{2} = 225

Solution

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} = 225 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} - 3^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

Popular Examples

(y^2)/9-(x^2)/(16)=1

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

vertices f(x)=-x^2-4x-3 vertices

f (x) = - x^{2} - 4 x - 3

x^{2} + y^{2} - 16 = 0

vertices (y^2}{25}-\frac{x^2)/4 =1 vertices

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

vertices (y^2)/(16)-(x^2)/(25)=1 vertices

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

Frequently Asked Questions (FAQ)

What is the foci 9x^2+25y^2=225 ?
The foci 9x^2+25y^2=225 is (4,0),(-4,0)