What is x^2+y^2-16=0 ?

The solution to x^2+y^2-16=0 is Circle with (a,b)=(0,0),r=4

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x^2+y^2-16=0

x^{2} + y^{2} - 16 = 0

(a, b) = (0, 0), r = 4

Solution steps

x^{2} + y^{2} - 16 = 0

Rewrite

x^{2} + y^{2} - 16 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

x^{2} = - 16 y

x^{2} - 6 x - 4 y + 5 = 0

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1

What is x^2+y^2-16=0 ?
The solution to x^2+y^2-16=0 is Circle with (a,b)=(0,0),r=4