What is (x^2)/(81)+(y^2)/(49)=1 ?

The solution to (x^2)/(81)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=9,b=7

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(x^2)/(81)+(y^2)/(49)=1

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 9, b = 7

Solution steps

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{81} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 9, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 9, b = 7

x^{2} + y^{2} = 20

12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

y^{2} = 24 x

x^{2} = 12 y

f (x) = x^{2} + 4 x + 5

What is (x^2)/(81)+(y^2)/(49)=1 ?
The solution to (x^2)/(81)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=9,b=7