What is -f(x)=4(x)^2+4(x)-4 ?

The solution to -f(x)=4(x)^2+4(x)-4 is Parabola with (h,k)=(-1/2 ,5),p=-1/16

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-f(x)=4(x)^2+4(x)-4

- f (x) = 4 (x)^{2} + 4 (x) - 4

(h, k) = (- \frac{1}{2}, 5), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 4 x - 4

Rewrite

- y = 4 x^{2} + 4 x - 4

in the standard form

4 (- \frac{1}{16}) (y - 5) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 5), p = - \frac{1}{16}

x^{2} - 4 y - 2 x - 40 y - 103 = 0

(x - 2)^{2} = - 32 (y - 5)

x^{2} + y - 3 = 0

(17 + x) = 34 x_{-} r (x)

x = 2 (y + 1)^{2} - 2

What is -f(x)=4(x)^2+4(x)-4 ?
The solution to -f(x)=4(x)^2+4(x)-4 is Parabola with (h,k)=(-1/2 ,5),p=-1/16