What is 8x^2+5x+k(x)=0 ?

The solution to 8x^2+5x+k(x)=0 is Parabola with (h,k)=(-5/16 , 25/32),p=-1/32

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8x^2+5x+k(x)=0

8 x^{2} + 5 x + k (x) = 0

(h, k) = (- \frac{5}{16}, \frac{25}{32}), p = - \frac{1}{32}

Solution steps

8 x^{2} + 5 x + y = 0

Rewrite

8 x^{2} + 5 x + y = 0

in the standard form

4 (- \frac{1}{32}) (y - \frac{25}{32}) = (x - (- \frac{5}{16}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{16}, \frac{25}{32}), p = - \frac{1}{32}

3 x^{2} + 4 y = 12

y^{2} = 3 x - 3

y < x^{2} + 1

x^{2} + 4 x + 2 y = 0

2 f (x) = x^{2} - 5 x + 4

What is 8x^2+5x+k(x)=0 ?
The solution to 8x^2+5x+k(x)=0 is Parabola with (h,k)=(-5/16 , 25/32),p=-1/32